In figure 2.18 angle QPR =90° seg PM perpendicular seg QR and Q-M-R PM =10 QM= 8 find QR solve
Answers
Answered by
2
Answer:
Post ur question with the figure first
Answered by
8
Answer:
We know that,
In a right angled triangle, the perpendicular segment to the hypotenuse from the opposite vertex, is the geometric mean of the segments into which the hypotenuse is divided.
Here, seg PM ⊥ seg QR
∴ PM²=QM×MR
⇒10²=8×MR
⇒100=8×MR
⇒MR=1008
⇒MR=252
Now,QR=QM+MR
=8+252
=16+252
=412
=20.5
Hence, QR = 20.5
Similar questions