Question

In figure (2) given below
. ABCD is an isosceles trapezium. Find the value of x and y
​

Answer 1

Answer:

value of x = 72 degree and y = 108degree

Step-by-step explanation:

Given: ABCD is an isosceles trapezium BC = AD

∠A = 2x, ∠C = y and ∠D = 3x

Since, ABCD is a trapezium and AB || DC

⇒ ∠A + ∠D = 180o

2x + 3x = 180o

5x = 180o

x = 180o/5 = 36o … (i)

Also, AB = BC and AB || DC

So, ∠A + ∠C = 180o

2x + y = 180o

2 × 36o + y = 180o

72o + y = 180o

y = 180o – 72o = 108o

Hence, value of x = 72 degree and y = 108degree