Question

In figure 3.80, if PQ=6,QR=10,PS=8 find TS.

Answer 1

Given conditions ⇒

PS = 8
PQ = 6
QR = 10
∴ PR = 10 + 6 = 16

We know that if the chord of the circle intersect externally then the products of the segments of the chords are equal. 

∴ PS × PT = PQ × PR
⇒ 8 × PT = 6 × 16
∴ PT = 12 

Now, PT = PS + TS
⇒ TS = PT - PS
∴ TS = 12 - 8
⇒ TS = 4 



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Answer 2

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