In Figure 4, line segments AB and CD bisect each other at O. AC L CD and BD L CD Prove that ACO = BDO and hence prove that AC = BD.
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Answer:
If it helps mark me as brainliest.
Step-by-step explanation:
In ∆OAC and ∆OBD,
AO=OB
CO=OD
Angle C= Angle D= 90°
So,
∆OAC=∆OBD. {RHS rule}. I can't find the symbol for congruent , so I have used equal instead.
So,
AC=BD. [CPCT]
BTW, you can also use SAS rule.
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hope this helps you!thank you!!
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