Question

in figure 7.33 BD and CE are altitudes of triangle ABC such that BD equal to C state the three pairs of equal parts in triangle CBD and triangle DBC second is triangle CBD congruent to triangle BAC why or why not is angle ACB is equal to angle abc why or why not​

Answer 1

Δ CBD  is congruent to ΔBCE  where BD = CE  & BD & CE are altitudes

Step-by-step explanation:

in Δ CBD & ΔBCE

BC = BC  ( common)

BD  = CE  ( Given)

∠BCE = ∠CDB = 90°   ( Altitide)

=> Δ CBD ≅ ΔBCE

Δ CBD  is congruent to ΔBCE

=> ∠ DCB = ∠EBC

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Answer 2

Answer:

Answer:∆CBD is congruent to ∆BCE

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CE

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudes

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:In ∆CBD & ∆BCE

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:In ∆CBD & ∆BCEBC=BC (Common)

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:In ∆CBD & ∆BCEBC=BC (Common) BD=CE (Given)

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:In ∆CBD & ∆BCEBC=BC (Common) BD=CE (Given)Angle BCE =Angle CBD 90° (Altitude)

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:In ∆CBD & ∆BCEBC=BC (Common) BD=CE (Given)Angle BCE =Angle CBD 90° (Altitude) => ∆CBD is congruent to ∆BCE

Answer:∆CBD is congruent to ∆BCEWhere BD= CE & BD &CEAre altitudesStep-by-step explanation:In ∆CBD & ∆BCEBC=BC (Common) BD=CE (Given)Angle BCE =Angle CBD 90° (Altitude) => ∆CBD is congruent to ∆BCE=> Angle BCE is Equel to Angle EBC