Question

in figure 9.47 ABCD is a rectangle with AB =6cm and BC = 4cm find the area of paralellogram ABEF

Answer 1

In rectangle ABCD, AB= 6cm.
In llgm, base, AB= 6cm,
And height of the llgm, AD= 4cm
Area of llgm = Base x Height
= 6cm x 4cm
= 24cm^2
Hence, the area of parallelogram is 24cm square.

Answer 2

the figure 9.47,
ABCD is a rectangle (given)
AB = 6cm (given)
BC = 4cm (given)

To be found,
$\bf{Area\: of \:parallelogram \:ABEF}$

We know that,
"Parallelograms on the same base and between same parallels are equal in area."

Rectangle ABCD and parallelogram ABEF lies on same base AB.

So,
$\bf{Area \:of\: rectangle \:ABCD = Area \:of\: parallelogram\: ABEF}$

$\bf{length × breadth = Area \:of\: parallelogram\: ABEF}$

$\bf{6 × 4 = Area \:of\: parallelogram\: ABEF}$

$\bf{24 = Area \:of\: parallelogram\: ABEF}$

Hence, area of the parallelogram ABEF is 24cm².