In figure, a circle touches all the four sides of a quadrilateral ABCD, whose sides AB = 6 cm,
BC 7 cm, and CD=4 cm. Find AD.
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Answer:
AD = 3cm @ns....
Step-by-step explanation:
◆ Let P,Q,R,S be the points where the circle touches the quadrilateral .From a point out side of the circle the two tangents to the circle are equal.
● AP = AS
● BP = BQ
● CR = CQ and DR = DS
:- Adding AP + BP + CR + DR = AS + BQ + CQ + DS AB + CD = AD + BC 6 + 4 = AD + 7 AD = 3 cm .❣️
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Answer:
AD= 3cm
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