In figure, AB = 28 m, AC = 24 m, BC = 20 m, CG = 32 m, AG = 40 m and D is mid-point of AG.
Find the area of the quadrilateral ABCD
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Answer:
AB= 28m
BC = 20m
CD = AB = 28m
DA = 20m
area of rectangle = l×b
= (28×20)m = 560m^2
In ∆CDG
CD = 28m
DG =20m
GC =32m
area of triangle = 1/2 × base × height
= 1/2 × CD × DG
= 1/2 × 28m × 20m
= 28m × 10m = 280m^2
area of quadrilateral = area of sq. + area of ∆
= (560 + 280)m^2
= 840m^2
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