Question

in figure ab and CD are two chords of a circle with Centre O if angle aob equal 110 and angle COD equal 110 then find the length of CP given that AB = 8 cm and op is perpendicular to CD​

Answer 1

Answer:

Step-by-step explanation:

since, angle AOB= angle COD =110°(given)

so, AB=CD

(chords that subtends equal angles at the centre are equal)

=CD=8cm

As,OP Perpendicular CD       (given)

So, CP=DP

(Perpendicular from centre to a chord bisect the chord)

=CP=1/2 ×CD

=CP=1/2 ×8

=CP=4cm.

I hope this help you.

Answer 2

Answer:

4 cm

AB = CD

because Angle AOB = angle COD

so CD is 8 cm

CD = CP + PD

CD = CP + CP (PERPENDICULAR BISECTION )

8 = 2CP

8/2= CP

4 = CP