Question

In figure AB and CD are two common tangents to two circles of unequal radii. Prove that AB = CD. ⚫️♒️

Answer 1

Answer:

Step-by-step explanation:

Just draw another tangent AD.

Now consider tangents AD & DC.

Since lenghts of tangents from an external point to a circle is equal,

                 AD = CD  ---------[1]

Similarly, AD = AB   ---------[2]    ( with the same reason) .

Now from [1] & [2]

                  AB = CD

                                 Hence proved