in figure , AB=BC,AD=EC prove that triangle ABE is congurent to triangle CBD
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∆ABE ≅ ∆CBD | SAS congruence rule. (iv) AP is the perpendicular bisector of BC. Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. AD is extended to intersect BC at P.
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