Question

in figure ABC is a right angled triangle at B . BD is drawn perpendicular to AC. show that angle DBA= angle DCB

Answer 1

Answer:

ABC is a right angle triangle.

we know tha sum of three angles of a triangle is 180 deg.

angle C = 90 - angle A

In triangle ABD,  angle ADB = 90 deg.

    Hence, angle ABD = 90 - angle A = angle C

In triangle CBD, angle 90 - angle C = angle B ,,  as angle BDC = 90 deg.

Answer 2

Answer: refer to attachment

Hope it helps