in figure ABCD is a quadrilateral ABCD =1/2 BD (am + CL)where am and CN are perpendicular on diagonal BD
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hey buddy!!
Here is your answer;
➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡➡
⭐⭐⤵
ar ( ABCD ) = ar(triangle ABD) + ar(triangle BCD)
= 1/2*BD*AM + 1/2*BD*CL
= 1/2*BD(AM+CL) (hence proved)
➡hope this helps you deaR ✌✌✌.
parth3772:
thx bhen
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