Question

in figure , abcd is asquare and triangle cde is an equilateral triangle.prove that ae=be

Answer 1

ABCD is a square and EDC is an equilateral triangle.
AD = BC
DE = CE
In triangleADE and triangleBCE,
AD = BC (given)
angelADE = angleBCE
DE = CE ( given)
Therefore,triangleADE is congruent to triangleBCE (SAS rule)
AE = BE (c.p.c.t)
Hence Proved