Question

in figure ABIIDE,AB=DE,ACIIBF and AC=DF prove that BCIIEF and BC=EF.
help...
fig in image...

Answer 1

in triangle ABC & triangle DEF

AB=DE......GIVEN
ANGLE BAC= ANGLE EDF(ANGLES BETWEEN THE EQUAL SIDES OF TWO TRIANGLES ARE EQUAL)
AC=DF........GIVEN

BY SAS RULE TRIANGLE ABC & TRIANGLE DEF ARE CONGURENT

BY C.P.C.T
BC=EF

AB||DE &AC||DF
THEREFORE BC||EF AS THEY ARE EQUAL LIKE SIDES AB & DE;AND AC&DF

Answer 2

Answer:

Step-by-step explanation: