In figure, angle 1 = angle 2 and triangle NSQ is congruent to triangle MTR, then prove that triangle PTS us similar to triangle PRQ
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Answer:In figure triangle NSQ≅ triangle MTR
Therefore,∠SQN=∠TRM
i.e., PQ=PR (sides opposite to equal angles are equal ) ...............1
And already it is given that ∠1=∠2
I.e.,PS=PT (sides opposite to equal angles are equal ) .............2
Subtracting 2 from 1 we get QS=TR
Therefore ST∥QR
Now as ST∥QR Therefore ∠1=∠SQR and ∠2=∠TRQ (corresponding angles)
And therefore ∠SPT=∠QPR
Then by AAA similarity criteria Triangle PTS∼ triangle PRQ.
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