Question 3.12: In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell?
Class 12 - Physics - Current Electricity Current Electricity Page-128
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emf of a cell A , E = 1.25 V
cell A gives the balance point at 35 cm length of the wire. e.g., l = 35cm
now, if we replaced the cell A by another cell B and then balance point shift to 63 cm .
Let emf of another cell B is E'
and balance point at l' = 63 cm
we know, The potential gradiant remains the same , as there is no change in the setting of standard circuit.
so, E/E' = l/l'
=> 1.25V/E' = 35cm/63cm
=> E' = 1.25 × 63/35 = 2.25 V
hence, emf of another cell B = 2.25 V
cell A gives the balance point at 35 cm length of the wire. e.g., l = 35cm
now, if we replaced the cell A by another cell B and then balance point shift to 63 cm .
Let emf of another cell B is E'
and balance point at l' = 63 cm
we know, The potential gradiant remains the same , as there is no change in the setting of standard circuit.
so, E/E' = l/l'
=> 1.25V/E' = 35cm/63cm
=> E' = 1.25 × 63/35 = 2.25 V
hence, emf of another cell B = 2.25 V
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