Question

in figure angle =75° angle EDC=75°,state which two triangle are similar and by which test​

Answer 1

In ∆ABC and ∆EDC, ∠ABC ≅ ∠EDC [Each angle is of measure 75°] ∠ACB ≅ ∠ECD [Common angle] ∴ ∆ABC ~ ∆EDC [AA test of similarity] One to one correspondence is ABC ↔ EDC