Math, asked by unnirc, 9 months ago

In figure angle BAC= 40 degree, BC=AC and CD= BD. Find angle ABD and angle BDC

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Answers

Answered by surbhimaurya

1

BAC=40

BC=AC

ABC=40

BCA=180-BAC+ABC

BCA=100

BCD=180-BCA

BCD=80

CD=BD

BCD=DBC

DBC=80

ABD=ABC+DBC

ABD=120

BDC=180-BCD+DBC

BDC=20

ABD=120&BDC=20

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