Question

in figure, angle MNP=90 degree seg NQ perpendicular to seg MP MQ=9 QP=4 find NQ

Answer 1

MN^2 + NP^2 = 169
MN^2 = 81+X^2
NP^2=16+X^2
81+2X^2+16=169
SO x =6

Answer 2

Answer:

Hello.......☺☺

Step-by-step explanation:

In ∆MNP, ∠ MNP = 900,

By Pythagoras theorem,

MN2 + NP2 = MP2

⇒ MN2 + NP2 = (MQ + QP)2

⇒ MN2 + NP2 = (13)2

⇒ MN2 + NP2 = 169 … (1)

In ∆MQN, ∠MQN = 900,

QN2 + MQ2 = MN2

⇒ QN2 + 92 = MN2

⇒ QN2 + 81 = MN2 …(2)

In ∆PQN, ∠PQN = 900,

QN2 + PQ2 = PN2

⇒ QN2 + 42 = PN2

⇒ QN2 + 16 = PN2 … (3)

Now (2) + (3)

⇒ QN2 + 81 + QN2 + 16 = MN2 + PN2

⇒ 2QN2 + 97 = 169 [from(1)]

⇒ 2QN2 = 72

⇒ QN2 = 36

Thus NQ = 6.

.

#OPE IT HELPS YOUUU