Question

In figure angle PQR PQ is equal to PR and Angle PRQ is equal to 60 degree find Angle QSR and angle QTR
it is urgent​

Answer 1

Answer:

sorry

Step-by-step explanation:

I can't help u in this question

Answer 2

Step-by-step explanation:

given:In△PQR,Bisectors of ∠Q&∠R meet at point S.

ToProve:∠QSR=90

∘

+

2

1

∠P

Proof:Let∠PQR=∠Q;∠QRP=∠R;∠QPR=2P

In△PQR

∠P+∠Q+∠R=180

∘

(sum of angles of a triangle)

⟹∠Q+∠R=180−P−(1)

In△SQR

∠QSR+

2

∠Q

+

2

∠R

=180

∘

(sum of angles of a triangle)

2

∠Q+∠R

=180−∠QSR

from(1)

2

180−∠P

=180−∠QSR

⟹90−

2

∠P

=180−∠QSR

⟹∠QSR=90+

2

∠P

Hence,proved