Question

in figure angle QRP is​

Answer 1

$\purple{hope \: it \: helps}$

Answer 2

∠PQR = 90° ( Angle in a semi-circle is a right angle )

∠PQR + ∠QPR + ∠QRP = 180°   ( Angle sum property of a Δ )

90 + ( 2x - 6 ) + ( 10x/3) = 180

270 + 6x - 18 + 10x = 540

16x = 288

x = 18°

∠QRP = (10x/3)

∠QRP = 60°