Question

in figure ax=by and ax is parallel to by prove that ap =bp​

Answer 1

Answer:

Given below:-

Step-by-step explanation:

In triangles AXP and BPY,

angle XAP = angle YBP (Alt. Int angles)

angle XPA = angle BPY ( Vert. Opp angles)

AX=BY (Given)

Therefore,

Triangle AXP ≈ Triangle BPY ( AAS)

So,

AP= BP (CPCT)

[QED] [PROVED]

Answer 2

Answer:

In triangle APX and BPY,

given, AX = BY

also they are parallel

So, let AB be transversal

Therefore

angle XAP = angle YBP

Also XY is a transversal

Therefore

angle AXP = angle BYP

also,

Angle XPA = YPB. (vertically opposite angle)

So 2 triangles are congruent by AAA congruency therefore

AP=BP by CPCT

Step-by-step explanation:

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