Question

In figure,BA perpendicular AC, DE perpendicular DF such that BA =DE and BF=EC. Show that triangle WBC congurence to triangle DEF.​

Answer 1

Answer:

Given : BA=DE

BF=EC

to prove: triangle ABC congruent to triangle DEF

Proof: BF=EC(given)

adding FC to both sides we get

BF+FC=EC+FC

BC=EF-------(i)

so in triangles ABC & DEF

AB= DE(given)

BC=EF(from (i)

angle BAC= Angle FDE(both 90⁰)

so triangle ABC Is congruent to triangle DEF (RHS congruncy)

Answer 2

Answer:

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