Subtract 4a - b + 3c from 6 - 2b + c and
find the value of the result when a = -2,b=0,
C = -1
Answers
Answered by
0
Step-by-step explanation:
6-2b+c-(4a-b+3c)
6-2b+c-4a+b-3c
6-b-4a-2c
a=-2 b=0 c=-1
6-0-4×(-2)-2×(-1)
6+8+2
16
Answered by
2
=(6-2b+c) - (4a-b+3c) =
=6-2b+c - 4a+b-3c
=6+b-2b-4a+c-3c
=6-b-4a-2c
=6-0-4×-2-2×-1
=6-0+8+2
=16
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