Question

Subtract 4a - b + 3c from 6 - 2b + c and
find the value of the result when a = -2,b=0,
C = -1​

Answer 1

Step-by-step explanation:

6-2b+c-(4a-b+3c)

6-2b+c-4a+b-3c

6-b-4a-2c

a=-2 b=0 c=-1

6-0-4×(-2)-2×(-1)

6+8+2

16

Answer 2

=(6-2b+c) - (4a-b+3c) =

=6-2b+c - 4a+b-3c

=6+b-2b-4a+c-3c

=6-b-4a-2c

=6-0-4×-2-2×-1

=6-0+8+2

=16