Question

in figure, BC⊥ AB , AD⊥ AB , AD = 9 and BC = 27, then find A(△ABC) / A(△ADB)​

Answer 1

SOLUTION: IN ∆ABC,BASE= AB

HEIGHT= BC= 27

IN ∆ADB,BASE= AB

HEIGHT= AD=9

HERE IN ∆ABC AND ∆ADB HAVE BASES,

THE RATIO OF AREAS OF TWO TRIANGLES WITH HAVING SAME BASES IS EQUAL TO THERE CORRESPONDING HEIGHTS

SO,∆ABC/ADB =BC/AD

∆ABC/∆ADB= 9/27

∆ABC/∆ADB= 1/3 OR 1:3

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