Question

In figure BE || CF and AB : BC = 1:2, prove that AE : EF = 1:2

Answer 1

Step-by-step explanation:

According to Thales theorem,

If a line DE is parallel to side BC of a ∆ABC with vertex A, then AD/DB = AE/EC.

Here,

AB/BC = AE/EF

So, AE:EF = 1:2

Hence Proved

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