In figure , DE || AC and DF || AE
prove that
BF/FE = BE/EC
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Answered by
1
Step-by-step explanation:
In ΔABC
DE∣∣AC
Line drawn parallel to one side of triangle, insects the other two sides. It divides the other side in same ratio.
EC
BE
=
DA
BD
__(i)
In ΔAEB
DF∣∣AE
Line drawn parallel to one side of triangle, intersects the other sides. It divides the other sides in same ratio.
FE
BF
=
DA
BD
__(ii)
From (i) & (ii)
EC
BE
=
FE
BF
∴ Hence proved.
Answered by
22
In ΔABC, given as, DE || AC
Thus, by using Basic Proportionality Theorem, we get,
∴BD/DA = BE/EC ………………………………………………(i)
In ΔABC, given as, DF || AE
Thus, by using Basic Proportionality Theorem, we get,
∴BD/DA = BF/FE ………………………………………………(ii)
From equation (i) and (ii), we get
BE/EC = BF/FE
Hence, proved.
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