Question

In figure find the area of the shaded region . (use under root35 = 5.9)


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ANSWER
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Answer 1

Answer:

40.8 sq. cm

Step-by-step explanation:

ΔBOC is right angled and BC is hypotenuse.

By Pythagoras theorem,

BC² =BO² + OC²

BC² = 12² + 5² = 169

BC = 13 cm.

Area of ΔBOC = 1/2 * b * h = 1/2 * 5 * 12 = 30 sq.cm.

Now using Heron's formula t o find Area of ΔABC

Area of triangle when 3 sides are known = √p(p-a)(p-b)(p-c)  where p = a + b+c

in ΔABC, a = 13 cm , b = 18 cm c = 11 cm

So p = a+b+c/2 = 13+18+11/2 = 42/2 = 21.

So area of ΔABC = √21 ( 21 -13)(21-18)(21-11) = √21 * 8 * 3 * 10  =

                = √3 * 7 *  8 * 3 * 2 * 5

                = √16 * 9 * 35 = 12√35 = 12 * 5.9 = 70.8 sq .cm.

So area of shaded region = Area of ΔABC - Area of ΔBOC

                                           = 70.8 - 30 = 40.8 sq. cm.

Answer 2

Answer ---->

_____________

40.8cm^2