in figure find X, futher find angle BOC, angle COD and angle AOD
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Answered by
80
x+20+x+x+10 = 180° { linear pair}
3x + 30 = 180
x+ 10 = 60
x = 50 °
use ,
angle BOC =》
X+ 2O = 50 + 20 = 70°
ANGLE COD =》
X = 50°
ANGLE AOD =》
X+ 10= 50 + 10 = 60°
3x + 30 = 180
x+ 10 = 60
x = 50 °
use ,
angle BOC =》
X+ 2O = 50 + 20 = 70°
ANGLE COD =》
X = 50°
ANGLE AOD =》
X+ 10= 50 + 10 = 60°
akash801:
hiii
Answered by
19
Step-by-step explanation:
X° + 10° + X °+ X° + 20° = 180°. (linear pair)
3 X + 30=180°
3x=150°
X =150÷3
x=50°
so angle BOC =X + 20°
=50 + 20
=70°
angle COD=X°=50°
angle AOD=X + 10=50 +10=60°
so, angle BOC 70°, angle COD 50°, and angle AOD 60°.
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