Question

in figure given below if LD perpendicular toMN, then prove that LM^2+DN^2=LN^2+MD^2

Answer 1

See the below picture

Answer 2

Step-by-step explanation:

In ∆LDM

LD²+MD² = LM²

In ∆LND

LD²+ND²=LN²

As LD is common

LM²-MD²=LN²-ND²

LM²+DN²=LN²+MD²

HENCE PROVED