in figure if Ab,,cd angle =40and angle prd=118 find x and y
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hope it helps.........
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Angle APQ=40 degree.
Therefore Angle x=40degree (alternate interior angles)
Angle PRD=118 degree.
Therefore Angle PRC=180-118=62degree.
Angle x+Angle PRC+Angle y=180 degree. (angle sum property of a triangle)
Implies that :40+62+y=180
102+y=180
y=180-102=78
Therefore x=40 degree & y=78 degree
Therefore Angle x=40degree (alternate interior angles)
Angle PRD=118 degree.
Therefore Angle PRC=180-118=62degree.
Angle x+Angle PRC+Angle y=180 degree. (angle sum property of a triangle)
Implies that :40+62+y=180
102+y=180
y=180-102=78
Therefore x=40 degree & y=78 degree
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