Question

in figure if ad is the bisector of angle A show that angle A B is greater than angle BD

Answer 1

If AD is the bisector of ∠A of triangle ABC, show that AB>DB. 
Given AD is the bisector of ∠A of triangle ABC 
Hence ∠DAB=∠DAC 
∠BDA is the exterior angle of the ∆DAC 
Hence ∠BDA> ∠DAC 
or ∠BDA > ∠DAB Since ∠DAC=∠DAB 
→ AB > BD In a triangle sides opposite to greater angle is greater.


this is the right answer ignore the first