In figure if AE || DC and AB = AC, find the value of ∠ABD.
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Answer:
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Solution :-
given that,
→ ∠ at line segment EA = 50°
So,
→ ∠ACB = 50° { since AE || DC , corresponding angles }
then,
→ ∠ABC = ∠ACB { since AB = AC , angle opposite to equal sides are equal in measure . }
→ ∠ABC = 50°
therefore,
→ ∠ABC + ∠ABD = 180° { Linear pair }
→ 50° + ∠ABD = 180°
→ ∠ABD = 180° - 50°
→ ∠ABD = 130° (Ans.)
Learn more :-
In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .
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