In figure, if ∠ATO = 40°, then find ∠AOB.
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Answer:
<AOB = 100°
Step-by-step explanation:
Given <ATO = 40°
Proof :
i) In ΔOAT , ΔOBT
OA = OB \* radii of a same circle\*
<OAT = <OBT = 90°
\* Angle between tangent and radius
through the point of contact *\
OT =OT \*common hypotenuse *\
∴ΔOAT ≅ ΔOBT \* RHS congruence rule *\
<ATO = < OTB /* C.P.C .T*/
∴<ATO +<OTB = 2<ATO
= 2×40° [ GIVEN ]
= 80°
ii) In OATB quadrilateral,
<AOB + <OBT + <BTA + <TAO = 360°
/* Angle sum property */
<AOB + 90° + 80° + 90° = 360°
⇒ <AOB = 360° - 260°
= 100°
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