Question

in figure ,if line pq and rs intersect at point t,such that angle prt =40degree,angle rpt=95degree and angle tsq=75degree,find angle sqt

Answer 1

my friend i thought your figure is not correct @@

Answer 2

Hello mate ☺

____________________________

Solution:

In ∆PRT, we have

∠PRT+∠RPT+∠RTP=180°   (Sum of three angles of a triangle =180°)

⇒40°+95°+∠RTP=180°

⇒∠RTP=180°−40°−95°=45°

∠RTP=∠QTS     (Vertically Opposite Angles)

Therefore, ∠QTS is also equal to 45°

In ∆STQ, we have

∠SQT+∠TSQ+∠QTS=180°  (Sum of three angles of a triangle =180°)

⇒∠SQT+75°+45°=180°

⇒∠SQT=180°−75°−45°=60°

I hope, this will help you.☺

Thank you______❤

_____________________________❤