In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is
equal to
(a) 2 cm (b) 3 cm (c) 4 cm (d) 5 cm
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Answer:
OC is perpendicular on chord AB
Therefore:-OC bisects the chord AB
=AC=CB
Now,
AC+CB=AB
AC+CB=8
AC=8/2
=4cm
∆OCA is a right angled triangle
2. 2. 2
THEREFORE:- AO =AC + OC
2. 2. 2
5. =. 4 + OC
2. 2. 2
5. - 4. = OC
2
OC = 9
OC=3
since,OD is radius of circle
THEREFORE:-OA=OD = 5cm
CD=OD-OC
5-3=2 cm
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