In figure if OM = 6cm is the perpendicular to the chord BC of length 13cm and AB = 1.5cm, then the radius of the outer circle is
a. 8cm
b. 10cm
c. 7.5cm
d. 14.5cm
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Answered by
0
Answer:
D is correct answer
AB+BM=14.5
and OM =6
then, use paythagoras theorem
Answered by
0
Answer:
b.10
Step-by-step explanation:
ab+BM=1.5+6.5=8
given om=6
therefore by Pythagoras theorem
oa²=om²+am²
=8²+6²
=64+36
=100
OA=10
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