In figure, if triangle PQR is isosceles in which angle Q = angle R
and LM || QR. If angle P= 40°, find angle LMR.
with steps
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Let angle 'B' angle 'Q' be x
then ,
2x + 40 = 180. ( angle sum property of ∆ )
2x = 140
x = 70
angle R = angle PML. ( Alternate interior angles of parallel lines.)
So angle PML = 70°
angle PML + angle LMR = 180°. ( linear pair )
70° + angle LMR = 180°
angle LMR = 180° - 70°
angle LMR = 110°
Hope it helps
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