Question

In figure is a right triangle ABC with ac=10cm and ab=6cm the area.
Determine the area of the triangular

Answer 1

By Pythagoras theorem you know the BC

Answer 2

Hence the area of ∆ABC is

$24 {cm}^{2}$

GIVEN

ABC is a right-angled triangle

AC = 10cm

AB = 6 cm

TO FIND

Area of the triangle.

SOLUTION

We can simply solve the above problem as follows

We know that,

Area of a right-angle triangle

$= \frac{1}{2} \times base \times height$

Where,

Base = BC

Height = 6cm

To find the length of BC we will apply Pythagoras' theorem in ∆ABC.

${AB}^{2} + {BC}^{2} = {AC}^{2}$

${BC}^{2} = {AC}^{2} - {AB}^{2}$

${BC}^{2} = 100 - 36$

BC = √64 = 8 cm

Putting the value of BC

$Area = \frac{1}{2} \times 8 \times 6$

$= 24 {cm}^{2}$

Hence the area of ∆ABC is

$24 {cm}^{2}$

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