in figure O is centre of circle .two chords ab and cd of circle intersect each other at point p inside the circle.prove that angle bpc=1/2 (angle aod+ angle boc)
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Please refer the above photograph for the used process
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skh2:
wait
in pbd the side pb is extended till a so the line becomes ab but there is no change in the angle so angle remains same
got it
ok
proving is done by wrong metho
method
the answer has been verified
so, how is it wrong??
angles of same segment are equal when both lines touch at circumference
ok it os actually theorem 9 of ncert class 9
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