Math, asked by sadudhoundiyal, 1 month ago

In figure, O is centre of the circle and ZAOB = 60° then find LACB

Attachments:

Answers

Answered by Anisha5119
3

Answer:

Given O is the centre of circle.

∠AOB=60

To find : ∠ACB, ∠ADB

∠ACB= 1/2 ∠AOB

(Angle subtended by the arcA at centre is twice the angle subtended by the arc on the circle)

∴ ∠ACB=30°

ACBD is a cyclic quadrilateral

We know that,

Opposite angles in a cyclic quadrilateral sum= 180 °

∠ACB+∠ADB=180°

30° +∠ADB=180°

∠ADB=150°

Hence

∠ACB=30°

∠ADB=150°

Attachments:
Answered by ItzStarling
1

Answer:

3+2

2

1

=

3+2

2

1

×

3−2

2

3−2

2

=

(3)

2

−(2

2

)

2

3−2

2

=

9−8

3−2

2

=3−2

2

=3−2(1.4)

=3−2.8

=0.2

3+2

2

1

=

3+2

2

1

×

3−2

2

3−2

2

=

(3)

2

−(2

2

)

2

3−2

2

=

9−8

3−2

2

=3−2

2

=3−2(1.4)

=3−2.8

=0.2

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