Question

in figure O is the centre of a circle ab is a chord and if the tangent of 8 a if angle aob is equal to 120 degree then find angle BAC​

Answer 1

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Answer 2

oa=ob both are radius so ∆oab is isosceles triangle

let √oba=√oab=x

√aob +√oba +√oab=180°

2x +120°=1800

x=30°

tangent make 90 degree with radius

so angle bac =90-30=60°

√BAC=60°
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