Question

in figure O is the centre of a circle PQ is a chord and the tangent PR at P makes an angel of 50 degree with PQ find angle POQ ​

Answer 1

Answer:

100 degree

Step-by-step explanation:

angle OPQ=90-50=40(tangent in contact with radius)

angleOQP=ANGLE OPQ =40 DEGREE(ISOCELES THEOREM)

BY ANGLE SUM PROPERTY

ANGLE POQ=100 DEGREE

PLZ MARK AS BRAINLIEST

Answer 2

Answer:

answer is angle POQ= 100°

Step-by-step explanation:

we know that radius is perpendicular to a tangent.

angleOPR = 90°

angleOPQ + angleQPR = 90°

angleOPQ + 50° = 90°

[ angleQPR is given]

angleOPQ = 40°

OP = OQ

[ radii of a circle]

angleOPQ=angleOQP=40°

[base angles of equal sides are equal]

In triangle POQ

angleOQP + anglePOQ + angleOPQ = 180°

[angle sum property of traingle]

40° + anglePOQ + 40° = 180°

anglePOQ + 80° = 180°

anglePOQ = 180° - 80°

anglePOQ = 100°