In figure OACB is a quadrant of a circle with centre O and radius 3.5cm.If OD is 2cm, find the area of quadrant OACB and shaded region.
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1
Answer:
(i)
Area of quadrant OACB=
4
Area of Circle
=
4
π×r
2
=
4
1
×
7
22
×3.5×3.5 =9.625cm
2
(ii)
Area of the shaded region = Area of Quadrant −Area of △BDO
=9.625−(
2
1
×3.5×2)
=6.125cm
2
Explanation:
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