in figure of triangle ABC ad is bisector of angle BAC and AD perpendicular to BC show that angle DAE = 1/2 (angle C - Angle B)
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Hello user
Since,
In the triangle ABC ad is bisector of angle BAC and AD perpendicular to BC
So , angle DAE = 90° - B .....
Also, Angle CAD = C - 90°
Since, angle DAE = Angle CAD, we get
2 × angle DAE = C - D
angle DAE = 1/2(C - D)
Since,
In the triangle ABC ad is bisector of angle BAC and AD perpendicular to BC
So , angle DAE = 90° - B .....
Also, Angle CAD = C - 90°
Since, angle DAE = Angle CAD, we get
2 × angle DAE = C - D
angle DAE = 1/2(C - D)
Answered by
5
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