In figure p is the mid point of side BC of a parallelogram ABCD such that angle.BAP = angle.DAP then AD=
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In figure, P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. Prove that AD = 2 CD. Firstly, use the property that sum of cointerior angles is 180°. Secondly, use the property that sum of all angles in a triangle is 180° and then prove the required result
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