Question

In figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ROS=1/2(∠QOS−∠POS).​

Answer 1

Answer:

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Step-by-step explanation:

∠ROS=90

∘

−∠POS−(i)

∠QOS=∠QOR+∠ROS=90

∘

+∠ROS

⇒90

∘

=∠QOS−∠ROS−(ii)

Substituting (ii) in (i) we get

∠ROS=∠QOS−∠ROS−∠POS

⇒2∠ROS=∠QOS−∠POS

⇒∠ROS=

2

1

(∠QOS−∠POS)

Hence proved.

solution

Answer 2

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