When a polynomial f(x) is divided by x-3 and x+6 , the respective remainders are 7 and 22. What is the remainder when f(x) is divided by (x-3)(x+6)
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f(x) = (x – 3)(some polynomial) + 7 so that f(3) = 7
f(x) = (x + 6)(some other polynomial) + 22 so that f( – 6 ) = 22
when f(x) is divided by a quadratic factor the remainder is of the form ax + b
f(x) = (x – 3)(x + 6)(yet another polynomial) + ax + b
subs x = 3: 7 = 3a + b
subs x = – 6: 22 = – 6a + b
subtracting these we get – 15 = 9a
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