Question

in figure PQ is a chord of a circle with center O & PT is a tangent .if /_QPT =60 then find /_PRQ?​

Answer 1

$\huge\star\underline\mathfrak\red{Answer:-}$

answer is 120

Step-by-step explanation:

given :PT is a tangent so ∠OPT=90

∠QPT =60

∠OPQ = ∠OPT-∠QPT

∠OPQ=90-60

∠OPQ=30

∠OPQ+∠OQP+POQ=180        (ANGLE SUM PROPERTY)

∠POQ=180-30-30

∠POQ=120

Angle OPQ= angle OQP = 30° ie.,

Angle POQ= 120°. Also, angle PRQ= ½ reflex angle POQ.

∠PRQ=1/2(360-120)

∠PRQ=240/2

∠PRQ=120